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Let $\quad X_{1}, X_{2}, X_{3}, X_{4}, X_{5}$ be i.i.d. random variables having a continuous distribution function. Then

$$P\left(X_{1}>X_{2}>X_{3}>X_{4}>X_{5} \mid X_{1}=\max \left(X_{1}, X_{2}, X_{3}, X_{4}, X_{5}\right)\right)$$

 equals

1. $\frac{1}{4}$

2. $\frac{1}{5}$

3. $\frac{1}{4 !}$

4. $\frac{1}{5 !}$
in Probability by Expert (2.4k points) | 10 views

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