Let $\quad X_{1}, X_{2}, X_{3}, X_{4}, X_{5}$ be i.i.d. random variables having a continuous distribution function. Then
$$P\left(X_{1}>X_{2}>X_{3}>X_{4}>X_{5} \mid X_{1}=\max \left(X_{1}, X_{2}, X_{3}, X_{4}, X_{5}\right)\right)$$
equals
1. $\frac{1}{4}$
2. $\frac{1}{5}$
3. $\frac{1}{4 !}$
4. $\frac{1}{5 !}$