CSIR UGC NET June 2019 Part B Question 23

Question

Answer 1

We will answer each part one by one. 

1. The given series is an alternating series of the from $\sum (-1)^na_n$ with $a_n=\frac 1n$ is a decreasing sequence that converges to zero. This by alternating series test it is convergent. The given statement is False.
2. It is a well-known harmonic series that is divergent. It is also False.
3. We know that $\sum \frac{1}{n^2}$ is convergent. Let us assume $\sum \frac{1}{n^2}=k>0$, for some k. For a fixed $m\in\mathbb N$ we have  $$\sum_{n=1}^{\infty}  \frac{1}{n^2}=\sum_{n=1}^{\infty}  \frac{1}{(n+m)^2}= k$$ Therefore, we have $$\sum_{m=1}^{\infty}\sum_{n=1}^{\infty}  \frac{1}{(n+m)^2}=k\sum_{m=1}^{\infty}  1$$Therefore the given series is divergent. It is also a False statement.
4. We already answered in part 3 that it is true.

The correct option is only 4.

Comments

Very nice explanation. Keep it up.