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If $y$ is a solution of $y(x)-\int_{0}^{x}(x-t) y(t) d t=1$

then which of the following is true?

1. $y$ is bounded but not periodic in $\mathbb{R}$

2. $y$ is periodic in $\mathbb{R}$

3. $\int_{\mathbb{R}} y(x) d x<\infty$

4. $\int_{\mathbb{R}} \frac{d x}{y(x)}<\infty$
in Differential Equation by Expert | 225 views

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